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Init super with existing instance?

Suppose I have:

class Super:
  def __init__(self,a):
     self.a = a
  def from_b(cls,b):
     return cls(b.to_a())
class Regular(Super):
   def __init__(self,b):
      # how to set my super to the output of
      super = super.from_b(b)

How do I correctly initialize the super class with the output of the super class method rather than init?

My OOP background is in C++ and I am continually getting into these scenarios due to the ability to overload constructors in C++, so a workaround for this would be awesome.


@shx2’s answer works but wastefully/awkwardly creates a throw-away Super object just to initialize the new Regular object with its a attribute.

If you have control over the source of Super, you can make the from_b method create an instance of the given subclass, and have the subclass call the from_b method in its __new__ method instead, so that a Regular object can be both created and initialized directly:

class Super:
    def __init__(self, a):
        self.a = a
    def from_b(cls, b):
        obj = super().__new__(cls)
        cls.__init__(obj, b.to_a())
        return obj
class Regular(Super):
    def __new__(cls, b):
        return super().from_b(b)

so that the following assertions will pass:

from unittest.mock import Mock
obj = Regular(Mock())
assert type(obj) is Regular
assert obj.a.to_a.is_called()